Probability Questions with Solutions
Tutorial on finding the probability of an event. In what follows, S is the sample space of the experiment in question and E is the event of interest. n(S) is the number of elements in the sample space S and n(E) is the number of elements in the event E.
Questions and their Solutions
Answers to the above exercises, more references and links.
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15 Probability Questions And Practice Problems for Middle and High School: Harder Exam Style Questions Included
Beki Christian
Probability questions and probability problems require students to work out how likely it is that something is to happen. Probabilities can be described using words or numbers. Probabilities range from 0 to 1 and can be written as fractions, decimals or percentages .
Here you’ll find a selection of probability questions of varying difficulty showing the variety you are likely to encounter in middle school and high school, including several harder exam style questions.
What are some real life examples of probability?
The more likely something is to happen, the higher its probability. We think about probabilities all the time.
For example, you may have seen that there is a 20% chance of rain on a certain day or thought about how likely you are to roll a 6 when playing a game, or to win in a raffle when you buy a ticket.
15 Probability Questions Worksheet
Get this 15 probability questions for your middle and high school students. Allows students tackle problems at their own pace and includes an answer key!
How to calculate probabilities
The probability of something happening is given by:
We can also use the following formula to help us calculate probabilities and solve problems:
- Probability of something not occuring = 1 – probability of if occurring P(not\;A) = 1 - P(A)
- For mutually exclusive events: Probability of event A OR event B occurring = Probability of event A + Probability of event B P(A\;or\;B) = P(A)+P(B)
- For independent events: Probability of event A AND event B occurring = Probability of event A times probability of event B P(A\;and\;B) = P(A) × P(B)
Probability question: A worked example
Question: What is the probability of getting heads three times in a row when flipping a coin?
When flipping a coin, there are two possible outcomes – heads or tails. Each of these options has the same probability of occurring during each flip. The probability of either heads or tails on a single coin flip is ½.
Since there are only two possible outcomes and they have the same probability of occurring, this is called a binomial distribution.
Let’s look at the possible outcomes if we flipped a coin three times.
Let H=heads and T=tails.
The possible outcomes are: HHH, THH, THT, HTT, HHT, HTH, TTH, TTT
Each of these outcomes has a probability of ⅛.
Therefore, the probability of flipping a coin three times in a row and having it land on heads all three times is ⅛.
Middle school probability questions
In middle school, probability questions introduce the idea of the probability scale and the fact that probabilities sum to one. We look at theoretical and experimental probability as well as learning about sample space diagrams and venn diagrams.
6th grade probability questions
1. Which number could be added to this spinner to make it more likely that the spinner will land on an odd number than a prime number?
Currently there are two odd numbers and two prime numbers so the chances of landing on an odd number or a prime number are the same. By adding 3, 5 or 11 you would be adding one prime number and one odd number so the chances would remain equal.
By adding 9 you would be adding an odd number but not a prime number. There would be three odd numbers and two prime numbers so the spinner would be more likely to land on an odd number than a prime number.
2. Ifan rolls a fair dice, with sides labeled A, B, C, D, E and F. What is the probability that the dice lands on a vowel?
A and E are vowels so there are 2 outcomes that are vowels out of 6 outcomes altogether.
Therefore the probability is \frac{2}{6} which can be simplified to \frac{1}{3} .
7th grade probability questions
3. Max tested a coin to see whether it was fair. The table shows the results of his coin toss experiment:
Heads Tails
26 41
What is the relative frequency of the coin landing on heads?
Max tossed the coin 67 times and it landed on heads 26 times.
\text{Relative frequency (experimental probability) } = \frac{\text{number of successful trials}}{\text{total number of trials}} = \frac{26}{67}
4. Grace rolled two dice. She then did something with the two numbers shown. Here is a sample space diagram showing all the possible outcomes:
What did Grace do with the two numbers shown on the dice?
Add them together
Subtract the number on dice 2 from the number on dice 1
Multiply them
Subtract the smaller number from the bigger number
For each pair of numbers, Grace subtracted the smaller number from the bigger number.
For example, if she rolled a 2 and a 5, she did 5 − 2 = 3.
8th grade probability questions
5. Alice has some red balls and some black balls in a bag. Altogether she has 25 balls. Alice picks one ball from the bag. The probability that Alice picks a red ball is x and the probability that Alice picks a black ball is 4x. Work out how many black balls are in the bag.
Since the probability of mutually exclusive events add to 1:
\begin{aligned} x+4x&=1\\\\ 5x&=1\\\\ x&=\frac{1}{5} \end{aligned}
\frac{1}{5} of the balls are red and \frac{4}{5} of the balls are blue.
6. Arthur asked the students in his class whether they like math and whether they like science. He recorded his results in the venn diagram below.
How many students don’t like science?
We need to look at the numbers that are not in the ‘Like science’ circle. In this case it is 9 + 7 = 16.
High school probability questions
In high school, probability questions involve more problem solving to make predictions about the probability of an event. We also learn about probability tree diagrams, which can be used to represent multiple events, and conditional probability.
9th grade probability questions
7. A restaurant offers the following options:
Starter – soup or salad
Main – chicken, fish or vegetarian
Dessert – ice cream or cake
How many possible different combinations of starter, main and dessert are there?
The number of different combinations is 2 × 3 × 2 = 12.
8. There are 18 girls and 12 boys in a class. \frac{2}{9} of the girls and \frac{1}{4} of the boys walk to school. One of the students who walks to school is chosen at random. Find the probability that the student is a boy.
First we need to work out how many students walk to school:
\frac{2}{9} \text{ of } 18 = 4
\frac{1}{4} \text{ of } 12 = 3
7 students walk to school. 4 are girls and 3 are boys. So the probability the student is a boy is \frac{3}{7} .
9. Rachel flips a biased coin. The probability that she gets two heads is 0.16. What is the probability that she gets two tails?
We have been given the probability of getting two heads. We need to calculate the probability of getting a head on each flip.
Let’s call the probability of getting a head p.
The probability p, of getting a head AND getting another head is 0.16.
Therefore to find p:
The probability of getting a head is 0.4 so the probability of getting a tail is 0.6.
The probability of getting two tails is 0.6 × 0.6 = 0.36 .
10th grade probability questions
10. I have a big tub of jelly beans. The probability of picking each different color of jelly bean is shown below:
If I were to pick 60 jelly beans from the tub, how many orange jelly beans would I expect to pick?
First we need to calculate the probability of picking an orange. Probabilities sum to 1 so 1 − (0.2 + 0.15 + 0.1 + 0.3) = 0.25.
The probability of picking an orange is 0.25.
The number of times I would expect to pick an orange jelly bean is 0.25 × 60 = 15 .
11. Dexter runs a game at a fair. To play the game, you must roll a dice and pick a card from a deck of cards.
To win the game you must roll an odd number and pick a picture card. The game can be represented by the tree diagram below.
Dexter charges players $1 to play and gives $3 to any winners. If 260 people play the game, how much profit would Dexter expect to make?
Completing the tree diagram:
Probability of winning is \frac{1}{2} \times \frac{4}{13} = \frac{4}{26}
If 260 play the game, Dexter would receive $260.
The expected number of winners would be \frac{4}{26} \times 260 = 40
Dexter would need to give away 40 × $3 = $120 .
Therefore Dexter’s profit would be $260 − $120 = $140.
12. A fair coin is tossed three times. Work out the probability of getting two heads and one tail.
There are three ways of getting two heads and one tail: HHT, HTH or THH.
The probability of each is \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}
Therefore the total probability is \frac{1}{8} +\frac{1}{8} + \frac{1}{8} = \frac{3}{8}
11th/12th grade probability questions
13. 200 people were asked about which athletic event they thought was the most exciting to watch. The results are shown in the table below.
A person is chosen at random. Given that that person chose 100m, what is the probability that the person was female?
Since we know that the person chose 100m, we need to include the people in that column only.
In total 88 people chose 100m so the probability the person was female is \frac{32}{88} .
14. Sam asked 50 people whether they like vegetable pizza or pepperoni pizza.
37 people like vegetable pizza.
25 people like both.
3 people like neither.
Sam picked one of the 50 people at random. Given that the person he chose likes pepperoni pizza, find the probability that they don’t like vegetable pizza.
We need to draw a venn diagram to work this out.
We start by putting the 25 who like both in the middle section. The 37 people who like vegetable pizza includes the 25 who like both, so 12 more people must like vegetable pizza. 3 don’t like either. We have 50 – 12 – 25 – 3 = 10 people left so this is the number that must like only pepperoni.
There are 35 people altogether who like pepperoni pizza. Of these, 10 do not like vegetable pizza. The probability is \frac{10}{35} .
15. There are 12 marbles in a bag. There are n red marbles and the rest are blue marbles. Nico takes 2 marbles from the bag. Write an expression involving n for the probability that Nico takes one red marble and one blue marble.
We need to think about this using a tree diagram. If there are 12 marbles altogether and n are red then 12-n are blue.
To get one red and one blue, Nico could choose red then blue or blue then red so the probability is:
Looking for more middle school and high school probability math questions?
- Ratio questions
- Algebra questions
- Trigonometry questions
- Venn diagram questions
- Long division questions
- Pythagorean theorem questions
Do you have students who need extra support in math? Give your students more opportunities to consolidate learning and practice skills through personalized math tutoring with their own dedicated online math tutor. Each student receives differentiated instruction designed to close their individual learning gaps, and scaffolded learning ensures every student learns at the right pace. Lessons are aligned with your state’s standards and assessments, plus you’ll receive regular reports every step of the way. Personalized one-on-one math tutoring programs are available for: – 2nd grade tutoring – 3rd grade tutoring – 4th grade tutoring – 5th grade tutoring – 6th grade tutoring – 7th grade tutoring – 8th grade tutoring Why not learn more about how it works ?
The content in this article was originally written by secondary teacher Beki Christian and has since been revised and adapted for US schools by elementary math teacher Katie Keeton.
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Probability Word Problems
In these lessons, we will learn how to solve a variety of probability problems.
Related Pages Probability Tree Diagrams Probability Without Replacement Theoretical vs. Experimental Probability More Lessons On Probability
Here we shall be looking into solving probability word problems involving:
- Probability and Sample Space
- Probability and Frequency Table
- Probability and Area
- Probability of Simple Events
- Probability and Permutations
- Probability and Combinations
- Probability of Independent Events
We will now look at some examples of probability problems.
Example: At a car park there are 100 vehicles, 60 of which are cars, 30 are vans and the remainder are lorries. If every vehicle is equally likely to leave, find the probability of: a) a van leaving first. b) a lorry leaving first. c) a car leaving second if either a lorry or van had left first.
Solution: a) Let S be the sample space and A be the event of a van leaving first. n(S) = 100 n(A) = 30
c) If either a lorry or van had left first, then there would be 99 vehicles remaining, 60 of which are cars. Let T be the sample space and C be the event of a car leaving. n(T) = 99 n(C) = 60
Example: A survey was taken on 30 classes at a school to find the total number of left-handed students in each class. The table below shows the results:
A class was selected at random. a) Find the probability that the class has 2 left-handed students. b) What is the probability that the class has at least 3 left-handed students? c) Given that the total number of students in the 30 classes is 960, find the probability that a student randomly chosen from these 30 classes is left-handed.
a) Let S be the sample space and A be the event of a class having 2 left-handed students. n(S) = 30 n(A) = 5
b) Let B be the event of a class having at least 3 left-handed students. n(B) = 12 + 8 + 2 = 22
c) First find the total number of left-handed students:
Total no. of left-handed students = 2 + 10 + 36 + 32 + 10 = 90
Here, the sample space is the total number of students in the 30 classes, which was given as 960.
Let T be the sample space and C be the event that a student is left-handed. n(T) = 960 n(C) = 90
Probability And Area
Example: ABCD is a square. M is the midpoint of BC and N is the midpoint of CD. A point is selected at random in the square. Calculate the probability that it lies in the triangle MCN.
Area of square = 2x × 2x = 4x 2
This video shows some examples of probability based on area.
Probability Of Simple Events
The following video shows some examples of probability problems. A few examples of calculating the probability of simple events.
- What is the probability of the next person you meeting having a phone number that ends in 5?
- What is the probability of getting all heads if you flip 3 coins?
- What is the probability that the person you meet next has a birthday in February? (Non-leap year)
This video introduces probability and gives many examples to determine the probability of basic events.
A bag contains 8 marbles numbered 1 to 8 a. What is the probability of selecting a 2 from the bag? b. What is the probability of selecting an odd number? c. What is the probability of selecting a number greater than 6?
Using a standard deck of cards, determine each probability. a. P(face card) b. P(5) c. P(non face card)
Using Permutations To Solve Probability Problems
This video shows how to evaluate factorials, how to use permutations to solve probability problems, and how to determine the number of permutations with indistinguishable items.
A permutation is an arrangement or ordering. For a permutation, the order matters.
- If a class has 28 students, how many different arrangements can 5 students give a presentation to the class?
- How many ways can the letters of the word PHEONIX be arranged?
- How many ways can you order 3 blue marbles, 4 red marbles and 5 green marbles? Marbles of the same color look identical.
Using Combinations To Solve Probability Problems
This video shows how to evaluate combinations and how to use combinations to solve probability problems.
A combination is a grouping or subset of items. For a combination, the order does not matter.
- The soccer team has 20 players. There are always 11 players on the field. How many different groups of players can be in the field at the same time?
- A student needs 8 more classes to complete her degree. If she has met the prerequisites for all the courses, how many ways can she take 4 class next semester?
- There are 4 men and 5 women in a small office. The customer wants a site visit from a group of 2 men and 2 women. How many different groups van be formed from the office?
How To Find The Probability Of Different Events?
This video explains how to determine the probability of different events. This can be found that can be found using combinations and basic probability.
- The probability of drawing 2 cards that are both face cards.
- The probability of drawing 2 cards that are both aces.
- The probability of drawing 4 cards all from the same suite.
A group of 10 students made up of 6 females and 4 males form a committee of 4. What is the probability the committee is all male? What is the probability that the committee is all female? What is the probability the committee is made up of 2 females and 2 males?
How To Find The Probability Of Multiple Independent Events?
This video explains the counting principle and how to determine the number of ways multiple independent events can occur.
- How many ways can students answer a 3-question true of false quiz?
- How many passwords using 6 digits where the first digit must be letters and the last four digits must be numbers?
- A restaurant offers a dinner special in which you get to pick 1 item from 4 different categories. How many different meals are possible?
- A door lock on a classroom requires entry of 4 digits. All digits must be numbers, but the digits can not be repeated. How many unique codes are possible?
How To Find The Probability Of A Union Of Two Events?
This video shows how to determine the probability of a union of two events.
- If you roll 2 dice at the same time, what is the probability the sum is 6 or a pair of odd numbers?
- What is the probability of selecting 1 card that is red or a face card?
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Probability Questions
The probability questions , with answers, are provided here for students to make them understand the concept in an easy way. The chapter Probability has been included in Class 9, 10, 11 and 12. Therefore, it is a very important chapter. The questions here will be provided, as per NCERT guidelines. Get Probability For Class 10 at BYJU’S.
The application of probability can be seen in Maths as well as in day to day life. It is necessary to learn the basics of this concept. The questions here will cover the basics as well as the hard level problems for all levels of students. Thus, students will be confident in solving problems based on it. Also, solving these probability problems will help them to participate in competitive exams, going further.
Definition: Probability is nothing but the possibility of an event occurring. For example, when a test is conducted, then the student can either get a pass or fail. It is a state of probability.
Also read: Probability
The probability of happening of an event E is a number P(E) such that:
0 ≤ P(E) ≤ 1
Probability Formula: If an event E occurs, then the empirical probability of an event to happen is:
P(E) = Number of trials in which Event happened/Total number of trials
The theoretical probability of an event E, P(E), is defined as:
P(E) = (Number of outcomes favourable to E)/(Number of all possible outcomes of the experiment)
Impossible event: The probability of an occurrence/event impossible to happen is 0. Such an event is called an impossible event.
Sure event: The probability of an event that is sure to occur is 1. Such an event is known as a sure event or a certain event.
Probability Questions & Answers
1. Two coins are tossed 500 times, and we get:
Two heads: 105 times
One head: 275 times
No head: 120 times
Find the probability of each event to occur.
Solution: Let us say the events of getting two heads, one head and no head by E 1 , E 2 and E 3 , respectively.
P(E 1 ) = 105/500 = 0.21
P(E 2 ) = 275/500 = 0.55
P(E 3 ) = 120/500 = 0.24
The Sum of probabilities of all elementary events of a random experiment is 1.
P(E 1 )+P(E 2 )+P(E 3 ) = 0.21+0.55+0.24 = 1
2. A tyre manufacturing company kept a record of the distance covered before a tyre needed to be replaced. The table shows the results of 1000 cases.
If a tyre is bought from this company, what is the probability that :
(i) it has to be substituted before 4000 km is covered?
(ii) it will last more than 9000 km?
(iii) it has to be replaced after 4000 km and 14000 km is covered by it?
Solution: (i) Total number of trials = 1000.
The frequency of a tyre required to be replaced before covering 4000 km = 20
So, P(E 1 ) = 20/1000 = 0.02
(ii) The frequency that tyre will last more than 9000 km = 325 + 445 = 770
So, P(E 2 ) = 770/1000 = 0.77
(iii) The frequency that tyre requires replacement between 4000 km and 14000 km = 210 + 325 = 535.
So, P(E 3 ) = 535/1000 = 0.535
3. The percentage of marks obtained by a student in the monthly tests are given below:
Based on the above table, find the probability of students getting more than 70% marks in a test.
Solution: The total number of tests conducted is 5.
The number of tests when students obtained more than 70% marks = 3.
So, P(scoring more than 70% marks) = ⅗ = 0.6
4. One card is drawn from a deck of 52 cards, well-shuffled. Calculate the probability that the card will
(i) be an ace,
(ii) not be an ace.
Solution: Well-shuffling ensures equally likely outcomes.
(i) There are 4 aces in a deck.
Let E be the event the card drawn is ace.
The number of favourable outcomes to the event E = 4
The number of possible outcomes = 52
Therefore, P(E) = 4/52 = 1/13
(ii) Let F is the event of ‘card is not an ace’
The number of favourable outcomes to F = 52 – 4 = 48
Therefore, P(F) = 48/52 = 12/13
5. Two players, Sangeet and Rashmi, play a tennis match. The probability of Sangeet winning the match is 0.62. What is the probability that Rashmi will win the match?
Solution: Let S and R denote the events that Sangeeta wins the match and Reshma wins the match, respectively.
The probability of Sangeet to win = P(S) = 0.62
The probability of Rashmi to win = P(R) = 1 – P(S)
= 1 – 0.62 = 0.38
6. Two coins (a one rupee coin and a two rupee coin) are tossed once. Find a sample space.
Solution: Either Head(H) or Tail(T) can be the outcomes.
Heads on both coins = (H,H) = HH
Head on 1st coin and Tail on the 2nd coin = (H,T) = HT
Tail on 1st coin and Head on the 2nd coin = (T,H) = TH
Tail on both coins = (T,T) = TT
Therefore, the sample space is S = {HH, HT, TH, TT}
7. Consider the experiment in which a coin is tossed repeatedly until a head comes up. Describe the sample space.
Solution: In the random experiment where the head can appear on the 1st toss, or the 2nd toss, or the 3rd toss and so on till we get the head of the coin. Hence, the required sample space is :
S= {H, TH, TTH, TTTH, TTTTH,…}
8. Consider the experiment of rolling a die. Let A be the event ‘getting a prime number’, B be the event ‘getting an odd number’. Write the sets representing the events
(ii) A and B
(iii) A but not B
(iv) ‘not A’.
Solution: S = {1, 2, 3, 4, 5, 6}, A = {2, 3, 5} and B = {1, 3, 5}
(i) A or B = A ∪ B = {1, 2, 3, 5}
(ii) A and B = A ∩ B = {3,5}
(iii) A but not B = A – B = {2}
(iv) not A = A′ = {1,4,6}
9. A coin is tossed three times, consider the following events.
P: ‘No head appears’,
Q: ‘Exactly one head appears’ and
R: ‘At Least two heads appear’.
Check whether they form a set of mutually exclusive and exhaustive events.
Solution: The sample space of the experiment is:
S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} and
Q = {HTT, THT, TTH},
R = {HHT, HTH, THH, HHH}
P ∪ Q ∪ R = {TTT, HTT, THT, TTH, HHT, HTH, THH, HHH} = S
Therefore, P, Q and R are exhaustive events.
P ∩ R = φ and
Therefore, the events are mutually exclusive.
Hence, P, Q and R form a set of mutually exclusive and exhaustive events.
10. If P(A) = 7/13, P(B) = 9/13 and P(A∩B) = 4/13, evaluate P(A|B).
Solution: P(A|B) = P(A∩B)/P(B) = (4/13)/(9/13) = 4/9.
Video Lesson
Probability important topics.
Probability Important Questions
Related Links
- Important Questions Class 9 Maths Chapter 15 Probability
- Important Questions Class 10 Maths Chapter 15 Probability
- Important Questions Class 11 Maths Chapter 16 Probability
- Important Questions Class 12 Maths Chapter 13 Probability
Practice Questions
Solve the following probability questions.
- Write the sample space for rolling two dice.
- If two coins are tossed simultaneously, what is the probability of getting exactly two heads?
- From a well-shuffled deck of 52 cards, what is the probability of getting a king?
- In a bag, there are 5 red balls and 7 black balls. What is the probability of getting a black ball?
- If the probability of an event happening is 0.7, then what is the probability of an event that will not happen?
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Teach yourself statistics
How to Solve Probability Problems
You can solve many simple probability problems just by knowing two simple rules:
- The probability of any sample point can range from 0 to 1.
- The sum of probabilities of all sample points in a sample space is equal to 1.
The following sample problems show how to apply these rules to find (1) the probability of a sample point and (2) the probability of an event.
Probability of a Sample Point
The probability of a sample point is a measure of the likelihood that the sample point will occur.
Example 1 Suppose we conduct a simple statistical experiment . We flip a coin one time. The coin flip can have one of two equally-likely outcomes - heads or tails. Together, these outcomes represent the sample space of our experiment. Individually, each outcome represents a sample point in the sample space. What is the probability of each sample point?
Solution: The sum of probabilities of all the sample points must equal 1. And the probability of getting a head is equal to the probability of getting a tail. Therefore, the probability of each sample point (heads or tails) must be equal to 1/2.
Example 2 Let's repeat the experiment of Example 1, with a die instead of a coin. If we toss a fair die, what is the probability of each sample point?
Solution: For this experiment, the sample space consists of six sample points: {1, 2, 3, 4, 5, 6}. Each sample point has equal probability. And the sum of probabilities of all the sample points must equal 1. Therefore, the probability of each sample point must be equal to 1/6.
Probability of an Event
The probability of an event is a measure of the likelihood that the event will occur. By convention, statisticians have agreed on the following rules.
- The probability of any event can range from 0 to 1.
- The probability of event A is the sum of the probabilities of all the sample points in event A.
- The probability of event A is denoted by P(A).
Thus, if event A were very unlikely to occur, then P(A) would be close to 0. And if event A were very likely to occur, then P(A) would be close to 1.
Example 1 Suppose we draw a card from a deck of playing cards. What is the probability that we draw a spade?
Solution: The sample space of this experiment consists of 52 cards, and the probability of each sample point is 1/52. Since there are 13 spades in the deck, the probability of drawing a spade is
P(Spade) = (13)(1/52) = 1/4
Example 2 Suppose a coin is flipped 3 times. What is the probability of getting two tails and one head?
Solution: For this experiment, the sample space consists of 8 sample points.
S = {TTT, TTH, THT, THH, HTT, HTH, HHT, HHH}
Each sample point is equally likely to occur, so the probability of getting any particular sample point is 1/8. The event "getting two tails and one head" consists of the following subset of the sample space.
A = {TTH, THT, HTT}
The probability of Event A is the sum of the probabilities of the sample points in A. Therefore,
P(A) = 1/8 + 1/8 + 1/8 = 3/8
Probability Practice Questions
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Unit 7: Probability
About this unit.
If you're curious about the mathematical ins and outs of probability, you've come to the right unit! Here, we'll take a deep dive into the many ways we can calculate the likelihood of different outcomes. From using simulations to the addition and multiplication rules, we'll build a solid foundation that will help us tackle statistical questions down the line.
Estimating probabilities using simulation
- Intro to theoretical probability (Opens a modal)
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Solved Probability Problems
Solved probability problems and solutions are given here for a concept with clear understanding.
Students can get a fair idea on the probability questions which are provided with the detailed step-by-step answers to every question.
Solved probability problems with solutions :
The graphic above shows a container with 4 blue triangles, 5 green squares and 7 red circles. A single object is drawn at random from the container.
Match the following events with the corresponding probabilities:
Number of blue triangles in a container = 4
Number of green squares = 5
Number of red circles = 7
Total number of objects = 4 + 5 + 7 = 16
(i) The objects is not a circle:
P(the object is a circle)
= Number of circles/Total number of objects
P(the object is not a circle)
= 1 - P(the object is a circle)
= (16 - 7)/16
(ii) The objects is a triangle:
P(the object is a triangle)
= Number of triangle/Total number of objects
(iii) The objects is not a triangle:
= Number of triangles/Total number of objects
P(the object is not a triangle)
= 1 - P(the object is a triangle)
= (16 - 4)/16
(iv) The objects is not a square:
P(the object is a square)
= Number of squares/Total number of objects
P(the object is not a square)
= 1 - P(the object is a square)
= (16 - 5)/16
(v) The objects is a circle:
(vi) The objects is a square:
Match the following events with the corresponding probabilities are shown below:
2. A single card is drawn at random from a standard deck of 52 playing cards.
Match each event with its probability.
Note: fractional probabilities have been reduced to lowest terms. Consider the ace as the highest card.
Total number of playing cards = 52
(i) The card is a diamond:
Number of diamonds in a deck of 52 cards = 13
P(the card is a diamond)
= Number of diamonds/Total number of playing cards
(ii) The card is a red king:
Number of red king in a deck of 52 cards = 2
P(the card is a red king)
= Number of red kings/Total number of playing cards
(iii) The card is a king or queen:
Number of kings in a deck of 52 cards = 4
Number of queens in a deck of 52 cards = 4
Total number of king or queen in a deck of 52 cards = 4 + 4 = 8
P(the card is a king or queen)
= Number of king or queen/Total number of playing cards
(iv) The card is either a red card or an ace:
Total number of red card or an ace in a deck of 52 cards = 28
P(the card is either a red card or an ace)
= Number of cards which is either a red card or an ace/Total number of playing cards
(v) The card is not a king:
P(the card is a king)
= Number of kings/Total number of playing cards
P(the card is not a king)
= 1 - P(the card is a king)
= (13 - 1)/13
(vi) The card is a five or lower:
Number of cards is a five or lower = 16
P(the card is a five or lower)
= Number of card is a five or lower/Total number of playing cards
(vii) The card is a king:
(viii) The card is black:
Number of black cards in a deck of 52 cards = 26
P(the card is black)
= Number of black cards/Total number of playing cards
3. A bag contains 3 red balls and 4 black balls. A ball is drawn at random from the bag. Find the probability that the ball drawn is
(ii) not black.
(i) Total number of possible outcomes = 3 + 4 = 7.
Number of favourable outcomes for the event E.
= Number of black balls = 4.
So, P(E) = \(\frac{\textrm{Number of Favourable Outcomes for the Event E}}{\textrm{Total Number of Possible Outcomes}}\)
= \(\frac{4}{7}\).
(ii) The event of the ball being not black = \(\bar{E}\).
Hence, required probability = P(\(\bar{E}\))
= 1 - P(E)
= 1 - \(\frac{4}{7}\)
= \(\frac{3}{7}\).
4. If the probability of Serena Williams a particular tennis match is 0.86, what is the probability of her losing the match?
Let E = the event of Serena Williams winning.
From the question, P(E) = 0.86.
Clearly, \(\bar{E}\) = the event of Serena Williams losing.
So, P(\(\bar{E}\)) = 1 - P(E)
= 1 - 0.86
= 0.14
= \(\frac{14}{100}\)
= \(\frac{7}{50}\).
5. Find the probability of getting 53 Sunday in a leap year.
A leap year has 366 days. So, it has 52 weeks and 2 days.
So, 52 Sundays are assured. For 53 Sundays, one of the two remaining days must be a Sunday.
For the remaining 2 days we can have
(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday).
So, total number of possible outcomes = 7.
Number of favourable outcomes for the event E = 2, [namely, (Sunday, Monday), (Saturday, Sunday)].
So, by definition: P(E) = \(\frac{2}{7}\).
6. A lot of 24 bulbs contains 25% defective bulbs. A bulb is drawn at random from the lot. It is found to be not defective and it is not put back. Now, one bulb is drawn at random from the rest. What is the probability that this bulb is not defective?
25% of 24 = \(\frac{25}{100}\) × 24 = 6.
So, there are 6 defective bulbs and 18 bulbs are not defective.
After the first draw, the lot is left with 6 defective bulbs and 17 non-defective bulbs.
So, when the second bulb is drwn, the total number of possible outcomes = 23 (= 6+ 17).
Number of favourable outcomes for the event E = number of non-defective bulbs = 17.
So, the required probability = P(E) = (\frac{17}{23}\).
The examples can help the students to practice more questions on probability by following the concept provided in the solved probability problems.
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How to Solve Probability Problems? (+FREE Worksheet!)
Do you want to know how to solve Probability Problems? Here you learn how to solve probability word problems.
Related Topics
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Step by step guide to solve Probability Problems
- Probability is the likelihood of something happening in the future. It is expressed as a number between zero (can never happen) to \(1\) (will always happen).
- Probability can be expressed as a fraction, a decimal, or a percent.
- To solve a probability problem identify the event, find the number of outcomes of the event, then use probability law: \(\frac{number\ of \ favorable \ outcome}{total \ number \ of \ possible \ outcomes}\)
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Probability problems – example 1:.
If there are \(8\) red balls and \(12\) blue balls in a basket, what is the probability that John will pick out a red ball from the basket?
There are \(8\) red balls and \(20\) a total number of balls. Therefore, the probability that John will pick out a red ball from the basket is \(8\) out of \(20\) or \(\frac{8}{8+12}=\frac{8}{20}=\frac{2}{5}\).
Probability Problems – Example 2:
A bag contains \(18\) balls: two green, five black, eight blue, a brown, a red, and one white. If \(17\) balls are removed from the bag at random, what is the probability that a brown ball has been removed?
If \(17\) balls are removed from the bag at random, there will be one ball in the bag. The probability of choosing a brown ball is \(1\) out of \(18\). Therefore, the probability of not choosing a brown ball is \(17\) out of \(18\) and the probability of having not a brown ball after removing \(17\) balls is the same.
Exercises for Solving Probability Problems
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- A number is chosen at random from \(1\) to \(10\). Find the probability of selecting a \(4\) or smaller.
- A number is chosen at random from \(1\) to \(50\). Find the probability of selecting multiples of \(10\).
- A number is chosen at random from \(1\) to \(10\). Find the probability of selecting of \(4\) and factors of \(6\).
- A number is chosen at random from \(1\) to \(10\). Find the probability of selecting a multiple of \(3\).
- A number is chosen at random from \(1\) to \(50\). Find the probability of selecting prime numbers.
- A number is chosen at random from \(1\) to \(25\). Find the probability of not selecting a composite number.
Download Probability Problems Worksheet
- \(\color{blue}{\frac{2}{5}}\)
- \(\color{blue}{\frac{1}{10}}\)
- \(\color{blue}{\frac{1}{2}}\)
- \(\color{blue}{\frac{3}{10}}\)
- \(\color{blue}{\frac{9}{25}}\)
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Probabilistic World
Probability Questions from the Real World (With Simulations)
Posted on August 2, 2020 Written by The Cthaeh Leave a Comment
Welcome to my introductory post to a large series that I’m starting today. The main purpose of this post is to get you in the mood for the posts to follow. Namely, exploring and solving interesting probability questions from the real world.
Most of my posts so far have been more on the theoretical side. In previous posts, I introduced important concepts from probability theory (and related fields like statistics and combinatorics):
- probabilities and sample spaces
- the law of large numbers and expected value
- permutations, combinations, and other combinatorics concepts
- mean and variance
- probability distributions
- Bayes’ theorem
And I’m going to continue introducing more concepts in the future, basic and advanced concepts alike. I personally find them fascinating in their own right. In the context of mathematics, they are interesting, thought provoking, and (some would say) even beautiful.
But they’re not just interesting, they’re also extremely useful. And when I say useful, I don’t just mean useful for mathematicians and scientists. I would argue they are a potentially useful tool for everybody.
Table of Contents
Skills in the real world
Think about the following skills for a moment:
- digesting nutrition
- absorbing water
You might find it strange that I’m calling these “skills”, but essentially they are. Of course, they are skills related to basic biological survival and, by definition, (almost) every living organism needs to have them in order to remain such.
Now, what about skills like:
- being fluent in a popular language
- detecting misinformation
- imagination and creativity
- performing CPR
In my opinion, skills like these (and many more) are always good to have. Regardless of your job, your age, or where you live. They are obviously not as essential as the previous category, but all of them are things that will allow you to achieve outcomes and take advantage of situations which you otherwise might not be able to.
Are probability theory skills useful in the real world?
So, where does having probability theory skills fit in all this? Well, I think it easily fits in the second category, though this isn’t as obviously true as some of the other skills in the list above. But think about it, what is probability theory really about? What does the ability to accurately calculate (or at least estimate) probabilities of events give you?
Well, probability theory is really about providing a measure for our uncertainty about an event’s occurrence and/or giving us insights about the frequency of an event’s long-term occurrence. In short, it helps us build good expectations about real-world events and phenomena. And, consequently, this helps us make better decisions (in the most general sense).
There’s uncertainty in so many fields. You can apply probability theory in science, games, economics, education, politics, and many more. Really, it’s hard to even come up with examples where probability theory can’t help. Regardless of what you do or find interesting, probability theory is a very useful tool to have under your belt.
Well, that’s how I feel about it anyway.
My motivation for these posts
Convincing you that probability theory is cool.
So, in an effort to justify my position, in this series I want to show you many probability questions from diverse areas in life. I’m going to start with simpler problems which are more fun than useful. And, eventually, I’m going to build up to more complicated ones.
More importantly, the process of solving these problems itself is useful in training your brain to think about probability questions. Often, the principles involved in solving simpler problems are the same (or at least similar) to the ones used for solving more complex ones.
Even though most of my posts so far have been theoretical, I’ve also written a few more practical ones. For example, I’ve shown you how to apply some of the theoretical concepts from the beginning for things like:
- solving the inverse problem
- calculating the bias of a coin
- predicting presidential elections
- cryptography
- Occam’s razor
But in more than one occasion I’ve been asked to give more examples of practical applications of the theoretical concepts, as well as just examples of solving probability related problems. Hopefully, this series will be a good first step in this direction.
Probability questions from the book Understanding Probability
People have also asked me for recommendations on probability theory and statistics books that give a decent overview of all important concepts from these fields.
For the first posts in this series, I’m going to use twelve probability questions from the book Understanding Probability: Chance Rules in Everyday Life by the author Henk Tijms . Tijms is a Dutch mathematician who specializes in probability theory and many related fields. If you’ve been interested in probability theory for long enough, this is a name that you’ve likely already heard.
I personally read this book a little less than 10 years ago while I was still finishing my master’s degree in cognitive neuroscience and back then I found it one of the most interesting books on the subject. I was pleasantly surprised when I recently received an email from Henk Tijms himself in which he shared some positive words about Probabilistic World. And he was kind enough to give me permission to use the probability questions from his book in my posts.
The very first image in this post (the funny laundry cartoon) is actually from the same book. It is the header image of the first chapter in which the twelve questions are introduced. I say introduced because the actual solutions are given in later chapters.
Anyway, if you’re new to probability theory and statistics and you’re looking for a good comprehensive book on the subject, I recommend you start with this book. Now, some of the concepts Henk Tijms discusses in the book are things that I’ve discussed myself. And the rest are things I’m going to discuss in the future. But when you read about the same concept explained in different ways by different people, this helps you consolidate your knowledge and understanding. This is an approach that I myself have used for a very long time and I find it very effective in learning.
So, I think the Understanding Probability book is a very good complement to my website.
Answering probability questions with simulations
My third main motive for this series is that I want to introduce you to the method of answering probability questions using simulations. This is an extremely important technique and sometimes it’s the only way certain questions can be answered. Why? Well, as you’ll see in future posts, there are a lot of problems for which we don’t have an analytic solution.
I’ve already used simulations in some of my previous posts:
- estimating coin bias
- the mean, the mode, and the median
- the law of large numbers
- expected value
- mean and variance of probability distributions
But, except for the first post in this list, I didn’t share the computer code used in these simulations. In order to show you how to use simulations yourself, in this series I’m going to be much more explicit with my explanations. And, for all simulations, I’m going to use my favorite programming language Python .
Python is an extremely powerful language and is one of the top choices for programmers, scientists, and basically anybody doing math-related programming for whatever reason. It’s also extremely beginner-friendly, easy to learn, and surprisingly similar to a natural language (English).
But don’t worry. If you don’t know anything about Python or programming in general, I’m going to make sure you still benefit from this series to the fullest extent. The simulations themselves are going to be ones you can perform even with a pen and paper. The role of the programming code is simply to make your computer perform the same steps automatically and much faster. Even without a programming background, you’ll gain intuition about the simulations.
For each probability question, I’m going to first show its analytic solution and then compare it to the answer we get with a simulation. Meaning, we’re going to reach the same answer from two entirely different paths. Which is going to be a very useful exercise for gaining intuition about the law of large numbers too!
What is a computer simulation?
In a nutshell, computer simulations are used for estimating probabilities empirically. This involves repeating the process that leads to the outcomes we’re interested in a large number of times. In the meantime, you simply keep track of the number of times each outcome occur. And the goal of the computer is to automate the steps in order to save you (lots of) time and effort.
In my post on the law of large numbers I showed you a few examples of such empirical estimates of probabilities. When it comes to the process of flipping a fair coin, the law guarantees that the percentage of flips that turn up “heads” will converge to the probability of “heads”. Click on the image below to see how the empirical estimate of the probability converges to the real probability as the number of simulated flips increases:
Click on the image to start/restart the animation.
Technically, you don’t need a computer for this. Just take a real coin or a real die and flip/roll it multiple times while keeping track of the outcomes. Of course, doing it like that is just extremely laborious (especially for more complicated processes), so it’s much better to use a computer simulation.
Bottom line is that, as long as you can simulate the outcome generating process with a computer (with programming or otherwise), you can empirically estimate the probability of any outcome. All thanks to the law of large numbers!
You know nothing about programming?
If you’ve never done any programming in your life but still want to run the simulations, you can do it. And I really mean that. You don’t have to first read a book about programming or Python. You don’t have to follow any online tutorials. None of that.
Don’t get me wrong, if you’re generally interested in getting into programming, you can do those things as well. But I’m a big fan of the philosophy called “learning by doing”. Especially for programming. If right now you’re thinking to yourself “Really? I can still run and understand the code even if know absolutely nothing about programming?”… Yes, trust me, you will be able to. And you’ll most likely start picking up programming concepts in the process, even if you don’t set this as an explicit goal.
For one thing, you’ll be able to run the code by simple copy/pasting even if you don’t understand it at all. But, like I said, Python is one of the most readable programming languages in existence and, even if you read the code as if you were reading plain English, you’ll still understand a lot. Especially combined with my brief explanations.
By the way, like I said earlier, even if you choose to skip the programming parts of my posts, you won’t lose anything from the analytic answers to the probability questions. But if you want to make your first steps in programming with actual probability questions, this is going to be a very good opportunity for you. And the only thing you’re going to need to start is Python itself.
Normally, you can simply download and install Python from the official Python website . But if you’re completely new to Python and/or programming, I strongly recommend installing it with the platform called Anaconda and using it with the web application called Jupyter Notebook that comes along with Anaconda.
Anaconda and Jupyter Notebook
You can download Anaconda from their official website . Definitely download the one with the latest Python 3 version (not Python 2) and just be careful to choose the right option for your operating system.
Once you download and install Anaconda, you can get familiar with it by following this quick guide . In particular, pay attention to the part about Jupyter Notebook . This is an awesome web application for running Python code (among other things) that is automatically installed when you install Anaconda.
Jupyter Notebook is an extremely popular tool among programmers working in fields like data science, machine learning, artificial intelligence, and many others intersecting with probability theory, statistics, and mathematics in general. It runs in your browser (the same one you’re currently reading this post from) and you’ll be able to run the code from my posts with it. Not only that, Anaconda will automatically install many popular Python packages that have a ton of useful functionality for the fields I mentioned.
If you want to get your hands dirty, you can take a look at this somewhat more extensive Jupyter Notebook tutorial . But you don’t have to read all these things at once, you can also do that when you start practicing with the code from my posts.
Bottom line, all you need to do to be able to start running the code form my posts is:
- Download and install Anaconda
- Learn how to run Jupyter Notebook from the command prompt (spoiler: the command is simply jupyter notebook )
- Optionally, go through the short tutorials I linked to
If you encounter any issues with these steps, let me know in the comments below and me or another reader will help you what that.
The probability questions
So, here are the titles of the twelve probability questions, as listed in the opening chapter of the book Understanding Probability:
- A birthday problem ( analytic solution and Python simulation )
- Probability of winning streaks
- A scratch-and-win lottery
- A lotto problem
- Hitting the jackpot
- Who is the murderer?
- A coincidence problem
- A sock problem
- A statistical test problem
- The best-choice problem
- The Monty Hall dilemma
- An offer you can’t refuse — or can you?
Many of these questions are famous problems in probability theory. But here Henk Tijms presents them in a fun and informal format. My posts won’t necessarily be in the same order, since answering some of these questions requires knowledge of concepts I haven’t talked about yet and I might put them on hold until I do.
Of course, these twelve questions are only a starting point. I’m going to write many other posts on other questions, some of them famous, some of them ones I came up with myself. And yet others which are simply interesting real-world questions that can be answered with probability theory.
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Tutorial on finding the probability of an event. In what follows, S is the sample space of the experiment in question and E is the event of interest. n(S) is the number of elements in the sample space S and n(E) is the number of elements in the event E. . Questions and their Solutions Question 1 A die is rolled, find the probability that an even number is obtained.
High school probability questions. In high school, probability questions involve more problem solving to make predictions about the probability of an event. We also learn about probability tree diagrams, which can be used to represent multiple events, and conditional probability. 9th grade probability questions
Probability tells us how often some event will happen after many repeated trials. You've experienced probability when you've flipped a coin, rolled some dice, or looked at a weather forecast. Go deeper with your understanding of probability as you learn about theoretical, experimental, and compound probability, and investigate permutations, combinations, and more!
The probability that you will draw a green or a red marble is \frac {5 + 15} {5+15+16+20} 5+15+16+205+15. We can also solve this problem by thinking in terms of probability by complement. We know that the marble we draw must be blue, red, green, or yellow. In other words, there is a probability of 1 that we will draw a blue, red, green, or ...
Solution: a) Let S be the sample space and A be the event of a van leaving first. n (S) = 100. n (A) = 30. Probability of a van leaving first: b) Let B be the event of a lorry leaving first. n (B) = 100 - 60 - 30 = 10. Probability of a lorry leaving first: c) If either a lorry or van had left first, then there would be 99 vehicles remaining ...
Also, solving these probability problems will help them to participate in competitive exams, going further. Definition: Probability is nothing but the possibility of an event occurring. For example, when a test is conducted, then the student can either get a pass or fail. It is a state of probability. Also read: Probability. The probability of ...
You might intuitively know that the likelihood is half/half, or 50%. But how do we work that out? Probability =. In this case: Probability of an event = (# of ways it can happen) / (total number of outcomes) P (A) = (# of ways A can happen) / (Total number of outcomes) Example 1. There are six different outcomes.
Unit 7: Probability. 0/1600 Mastery points. Basic theoretical probability Probability using sample spaces Basic set operations Experimental probability. Randomness, probability, and simulation Addition rule Multiplication rule for independent events Multiplication rule for dependent events Conditional probability and independence.
Solution: The sum of probabilities of all the sample points must equal 1. And the probability of getting a head is equal to the probability of getting a tail. Therefore, the probability of each sample point (heads or tails) must be equal to 1/2. Example 2 Let's repeat the experiment of Example 1, with a die instead of a coin.
Probability is traditionally considered one of the most difficult areas of mathematics, since probabilistic arguments often come up with apparently paradoxical or counterintuitive results. Examples include the Monty Hall paradox and the birthday problem. Probability can be loosely defined as the chance that an event will happen.
Practice Questions. Previous: Direct and Inverse Proportion Practice Questions. Next: Reverse Percentages Practice Questions. The Corbettmaths Practice Questions on Probability.
Twenty problems in probability This section is a selection of famous probability puzzles, job interview questions (most high-tech companies ask their applicants math questions) and math competition problems. Some problems are easy, some are very hard, but each is interesting in some way. Almost all problems
Finding the probability of a simple event happening is fairly straightforward: add the probabilities together. For example, if you have a 10% chance of winning $10 and a 25% chance of winning $20 then your overall odds of winning something is 10% + 25% = 35%. This only works for mutually exclusive events (events that cannot happen at the same ...
Learn the basics probability questions with the help of our given solved examples that help you to understand the concept in the better way. ... Sol: Probability of the problem getting solved = 1 - (Probability of none of them solving the problem) Probability of problem getting solved = 1 - (5/7) x (3/7) x (5/9) = (122/147)
Unit 7: Probability. If you're curious about the mathematical ins and outs of probability, you've come to the right unit! Here, we'll take a deep dive into the many ways we can calculate the likelihood of different outcomes. From using simulations to the addition and multiplication rules, we'll build a solid foundation that will help us tackle ...
Students can get a fair idea on the probability questions which are provided with the detailed step-by-step answers to every question. Solved probability problems with solutions: 1. The graphic above shows a container with 4 blue triangles, 5 green squares and 7 red circles. A single object is drawn at random from the container.
To solve a probability problem identify the event, find the number of outcomes of the event, then use probability law: \(\frac{number\ of \ favorable \ outcome}{total \ number \ of \ possible \ outcomes}\)
Exams with Solutions. pdf. 470 kB. 18.05 Introduction to Probability and Statistics (S22), Exam 1 Review: all questions: solutions. pdf. 144 kB. 18.05 Introduction to Probability and Statistics (S22), Exam 1 Review: practice 1: solutions. pdf.
Take a guided, problem-solving based approach to learning Probability. These compilations provide unique perspectives and applications you won't find anywhere else. Probability Fundamentals
Namely, exploring and solving interesting probability questions from the real world. Most of my posts so far have been more on the theoretical side. In previous posts, I introduced important concepts from probability theory (and related fields like statistics and combinatorics): ... Many of these questions are famous problems in probability ...
Solve probability word problems step by step. probability-problems-calculator. en. Related Symbolab blog posts. High School Math Solutions - Systems of Equations Calculator, Elimination. A system of equations is a collection of two or more equations with the same set of variables. In this blog post,...
Probability Equation Questions Name: _____ Instructions • Use black ink or ball-point pen. • Answer all questions. • Answer the questions in the spaces provided - there may be more space than you need. • Diagrams are NOT accurately drawn, unless otherwise indicated. • You must show all your working out. Information
Probability Problem Solver. Enter any math problem or upload an image. Solve for 𝑥 in the following equation 3𝑥 + 11 = 32. A car travels from point A to B in 3 hours and returns back to point A in 5 hours. Points A and B are 150 miles apart along a straight highway.