case study questions for class 7 maths exponents and powers

• Exponents and Powers Class 7 Case Study Questions Maths Chapter 11

Last Updated on September 7, 2024 by XAM CONTENT

Hello students, we are providing case study questions for class 7 maths. Case study questions are the new question format that is introduced in CBSE board. The resources for case study questions are very less. So, to help students we have created chapterwise case study questions for class 7 maths. In this article, you will find case study questions for CBSE Class 7 Maths Chapter 11 Exponents and Powers. It is a part of Case Study Questions for CBSE Class 7 Maths Series.

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Case Study Questions on Exponents and Powers

Bacteria can divide every 15 minutes. So one bacterium can multiply to 2 in 30 minutes, 4 in 45 minutes and so on.

Q. 1. How many bacteria will be there in 4 hours. (a) 65536 (b) 327680 (c) 131072 (d) 262144

Ans. Option (a) is correct. Explanation: Bacteria multiplies every 15 minutes So, it multiplies in every 4 hours $(4 \times 60) 240$ minutes

$$ =\frac{240}{15}=16 \text { times } $$

So, number of bacteria in 4 hours

$$ \begin{aligned} & =2^{16} \\ & =2 \times 2 \times 2….. \\ & =65536 \end{aligned} $$

Q. 2. How many bacteria will be there in 1 hour? (a) 2 2 (b) 2 4 (c) 2 6 (d) 2 8

Ans. Option (b) is correct. Explanation: Bacteria multiplies every 15 minutes So, it multiplies in 1 hour $(1 \times 60) 60$ minutes

$$ =\frac{60}{15}=4 \text { times } $$

So, number of bacteria in 1 hour

$$ =2^4 \text { or } 16 $$

Q. 3. Write 655360000 in scientific notation. (a) 6.5 × 10 8 (b) 6.55 × 10 7 (c) 6.553 × 10 6 (d) 6.5536 × 10 5

Ans. Option (a) is correct. Explanation: First factor between 1 and 10 is 6.5 and second factor 10 is raised to the power 8 as decimal is shifted 8 places.

Q. 4. Write 7.9 × 10 6 in standard form

Sol. 7.9 × 10 6 = 7.9 × 1000000 = 7900000

Q. 5. Simplify: (–5) 3 ÷ (–5) 6

$$ \begin{aligned} (-5)^3 \div(-5)^6 & =(-5)^{3-6} \\ & =(-5)^{-3} \\ & =\left(\frac{1}{-5}\right)^3=\frac{-1}{125} \end{aligned} $$

• Visualizing Solid Shapes Class 7 Case Study Questions Maths Chapter 13
• Symmetry Class 7 Case Study Questions Maths Chapter 12
• Algebraic Expressions Class 7 Case Study Questions Maths Chapter 10
• Perimeter and Area Class 7 Case Study Questions Maths Chapter 9
• Rational Numbers Class 7 Case Study Questions Maths Chapter 8
• Comparing Quantities Class 7 Case Study Questions Maths Chapter 7
• Triangle and its Properties Class 7 Case Study Questions Maths Chapter 6
• Lines and Angles Class 7 Case Study Questions Maths Chapter 5
• Simple Equations Class 7 Case Study Questions Maths Chapter 4
• Data Handling Class 7 Case Study Questions Maths Chapter 3

Fractions and Decimals Class 7 Case Study Questions Maths Chapter 2

Integers class 7 case study questions maths chapter 1, topics from which case study questions may be asked.

• Laws of exponents
• Decimal number system
• Expressing large numbers in the standard form

A number multiplied by itself many numbers of times can be expressed in the exponential notation as 2 × 2 × 2 × 2 × 2 = 2 5 ; where 2 is the base and 5 is the exponent index or power

Case study questions from the above given topic may be asked.

Exponents are also called Powers or Indices . The exponent says how many times to use the number in a multiplication .

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Frequently Asked Questions (FAQs) on Exponents and Powers Case Study

Q1: what are exponents.

A1: Exponents represent repeated multiplication of a base number.

Q2: What is the difference between base and exponent?

A2: In the expression a n , a is the base, which is the number being multiplied, and n is the exponent, which indicates how many times the base is multiplied by itself.

Q3: What is a power?

A3: Power refers to the entire expression involving a base and an exponent.

Q4: What happens when an exponent is zero?

A4: Any non-zero number raised to the power of zero is equal to 1.

Q5: What is a negative exponent?

A5: A negative exponent represents the reciprocal of the base raised to the positive exponent.

Q6: How do you express large numbers using exponents?

A6: Large numbers can be expressed using exponents by converting them into powers of 10.

Q7: H ow do you divide numbers with the same base using exponents?

A7: When dividing numbers with the same base, subtract the exponents.

Q10: Are there any online resources or tools available for practicing Exponents and Powers case study questions?

A10: We provide case study questions for CBSE Class 7 Maths on our  website . Students can visit the website and practice sufficient case study questions and prepare for their exams. If you need more case study questions, then you can visit Physics Gurukul website. they are having a large collection of case study questions for all classes.

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Case Study Questions for Class 7 Maths Chapter 13 Exponents and Powers

• Last modified on: 1 year ago
• Reading Time: 7 Minutes

Here in this article, we are providing case study questions for Class 7 Maths Chapter 13 Exponents and Powers.

Maths Class 7 Chapter List

Latest chapter list (2023-24).

There is total 13 chapters.

Chapter 1 Integers Case Study Questions Chapter 2 Fractions and Decimals Case Study Questions Chapter 3 Data Handling Case Study Questions Chapter 4 Simple Equations Case Study Questions Chapter 5 Lines and Angles Case Study Questions Chapter 6 The Triangles and its Properties Case Study Questions Chapter 7 Comparing Quantities Case Study Questions Chapter 8 Rational Numbers Case Study Questions Chapter 9 Perimeter and Area Case Study Questions Chapter 10 Algebraic Expressions Case Study Questions Chapter 11 Exponents and Powers Case Study Questions Chapter 12 Symmetry Case Study Questions Chapter 13 Visualising Solid Shapes Case Study Questions

Old Chapter List

Chapter 1 Integers Chapter 2 Fractions and Decimals Chapter 3 Data Handling Chapter 4 Simple Equations Chapter 5 Lines and Angles Chapter 6 The Triangles and its Properties Chapter 7 Congruence of Triangles Chapter 8 Comparing Quantities Chapter 9 Rational Numbers Chapter 10 Practical Geometry Chapter 11 Perimeter and Area Chapter 12 Algebraic Expressions Chapter 13 Exponents and Powers Chapter 14 Symmetry Chapter 15 Visualising Solid Shapes

Deleted Chapter:

• Chapter 7 Congruence of Triangles
• Chapter 10 Practical Geometry

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6. Transparent Workflow Display: Document your solution with transparency, showcasing intermediate calculations and steps taken. This not only helps track progress but also offers insight into your analytical process.

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8. Step Explanation: Accompany each step with an explanatory note. This reinforces your grasp of concepts and demonstrates effective application.

9. Realistic Application: When the case study pertains to real-world scenarios, infuse practical reasoning and logic into your solution. This ensures alignment with real-life implications.

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11. Solution Recap: Before submission, revisit your solution to guarantee comprehensive coverage of the problem and a well-organized response.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format.

13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration.

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Important Questions for CBSE Class 7 Maths Chapter 13 - Exponents and Powers

• Class 7 Important Question
• Chapter 13: Exponents And Powers

CBSE Class 7 Maths Chapter - 13 Important Questions Exponents and Powers - Free PDF Download

Discover essential questions for Class 7 Maths Chapter 13 in a convenient PDF format, meticulously reviewed by subject experts to ensure accuracy. Access reliable and error-free Exponents and Powers Class 7 important question solutions. Click the provided link to download all NCERT solutions for Chapter 10. Explore additional Class 7 Maths Chapter 13 extra questions for a comprehensive understanding of the topic.

Vedantu, a platform offering free CBSE Solutions (NCERT) and study materials, is a valuable resource for students. Those seeking enhanced solutions can benefit from downloading Class 7 Maths NCERT Solutions, aiding in thorough syllabus revision and improved exam scores. Register online for NCERT Solutions Class 7 Science tuition on Vedantu.com to boost your performance in CBSE board examinations.

Study Important Questions for Class 7 Maths Chapter 13 - Exponents and Powers

Very short answer questions                                                                  1 mark.

1. Find $\mathbf{{2^8}}$.

Ans: Given: ${2^8}$

We need to find the value of the given exponent.

We can rewrite ${2^8}$ to find its value as

${2^8} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$

${2^8} = 256$

2. Express the following in exponential form $\mathbf{2 \times 2 \times a \times a}$.

Ans: Given: $2 \times 2 \times a \times a$

We need to write the given expression as an exponential form.

A number can be written in its exponential form if we raise the power of the number by the exponent.

Therefore, exponential form of $2 \times 2 \times a \times a$ is

$2 \times 2 \times a \times a $

$ = {2^2} \times {a^2} $

$ = 4{a^2} $

3. Find $\mathbf{{( - 4)^3}}$.

Ans: Given: ${( - 4)^3}$

We need to find the value of a given exponent.

We can rewrite ${( - 4)^3}$ to find its value as

${( - 4)^3} =  - 4 \times  - 4 \times  - 4 $

${( - 4)^3} =  - 64 $

4. $\mathbf{{a^m} \times {a^n}}$=_______?

Ans: Given: ${a^m} \times {a^n}$

We need to fill in the blanks.

Therefore, ${a^m} \times {a^n}$$ = \underline {{a^{m + n}}} $

5. $\mathbf{{a^0} = \_\_\_\_\_?}$

Ans: Given: ${a^0}$

We need to find the value of a given expression.

We know that if $0$ is the power of any number then the value of the number is always $1.$

Therefore, ${a^0} = \underline {1.} $

Short Answer Questions                                                                          2 Mark

6. Express 16807 in exponential form.

Ans: Given: $16807$

We need to express the given number in exponential form.

Exponential form is a way to represent a number in repeated multiplications of the same number.

So, we can write $16807$ as $16807 = 7 \times 7 \times 7 \times 7 \times 7 $

$16807 = {7^5} $

7. Identify which is greater $\mathbf{{2^7}{\text{ or }}{7^2}}$.

Ans: Given: exponents ${2^7},{7^2}$

We need to find which exponent is greater. 

We will find the value of each exponent and then compare it.

We can write the exponents as

${2^7} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 $ 

${2^7} = 128 $

${7^2} = 7 \times 7 $

${7^2} = 49 $

Clearly, we can see that 

${2^7} > {7^2}$

8. Simplify $\mathbf{{7^3} \times {2^5}}$.

Ans: Given: ${7^3} \times {2^5}$

We need to simplify the given exponential expression.

We can simplify the given expression as 

${7^3} \times {2^5} = 7 \times 7 \times 7 \times 2 \times 2 \times 2 \times 2 \times 2$

${7^3} = 343 \times 32 $

${7^3} = 10976 $

9. Write 1024 as a power of 2.

Ans: Given: $1024$

We need to write the given expression as power of $2$

Break $1024$ in factors of 2 and write as exponents.

Therefore, $1024$ as power of $2$ will be written as

$1024 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 $

$\Rightarrow 1024 = {2^{10}} $

10. Using laws, find the value of $\mathbf{\left( {{3^{15}} \div {3^{10}}} \right) \times {3^2}}$.

Ans: Given: $\left( {{3^{15}} \div {3^{10}}} \right) \times {3^2}$

We need to find the value of a given expression using laws.

We know that

$\dfrac{{{a^m}}}{{{a^n}}} = {a^{m - n}} $

${a^m} \times {a^n} = {a^{m + n}} $

Using these laws, the value of $\left( {{3^{15}} \div {3^{10}}} \right) \times {3^2}$ will be

$= \left( {{3^{15}} \div {3^{10}}} \right) \times {3^2} $

$= \dfrac{{{3^{15}}}}{{{3^{10}}}} \times {3^2} $

$= {3^{15 - 10}} \times {3^2} $

$= {3^5} \times {3^2} $

$= {3^{5 + 2}} $

 $= 2187 $

11. Find $\mathbf{8 \times {10^5} + 0 \times {10^4} + 3 \times {10^3} + 2 \times {10^2} + 0 \times {10^1} + 5 \times {10^0}}$.

Ans: Given: $8 \times {10^5} + 0 \times {10^4} + 3 \times {10^3} + 2 \times {10^2} + 0 \times {10^1} + 5 \times {10^0}$

We need to find the value of the given expression.

We will solve the given exponents and then add them.

Therefore, the value of $8 \times {10^5} + 0 \times {10^4} + 3 \times {10^3} + 2 \times {10^2} + 0 \times {10^1} + 5 \times {10^0}$ will be

$= 8 \times 100000 + 0000 + 3 \times 1000 + 2 \times 100 + 00 + 5 \times 1 $

$= 800000 + 0 + 3000 + 200 + 0 + 5 $

$= 803205 $ 

12. Say True or False and Justify.

$\mathbf{{5^2} > {4^3}}$

Ans: Given: ${5^2} > {4^3}$

We need to find if the given expression is true or false.

We will solve the exponents and then compare them.

${5^2} = 25 $

${4^3} = 64 $

$25 < 64 $

$\Rightarrow {5^2} < {4^3} $

Therefore, the expression is False.

$\mathbf{{5^0} = {343^0}}$

Ans: Given: ${5^0} = {343^0}$

${5^0} = 1 $

${343^0} = 1 $

$\therefore {5^0} = {343^0} $

Therefore, the expression is true.

13. Find the value of $\mathbf{\left( {{3^0} + {2^0}} \right) \times {5^1}}$.

Ans: Given: $\left( {{3^0} + {2^0}} \right) \times {5^1}$

We know that ${a^0} = 1$

Therefore, the value of $\left( {{3^0} + {2^0}} \right) \times {5^1}$ will be

$= \left( {{3^0} + {2^0}} \right) \times {5^1} $

$= (1 + 1) \times 5 $

$= 2 \times 5 $

14. Find $\mathbf{\left( {\dfrac{{{a^6}}}{{{a^4}}}} \right) \times {a^{ - 2}} \times {a^0}}$.

Ans: Given: $\left( {\dfrac{{{a^6}}}{{{a^4}}}} \right) \times {a^{ - 2}} \times {a^0}$

We know that 

${a^0} = 1 $ 

Therefore, $\left( {\dfrac{{{a^6}}}{{{a^4}}}} \right) \times {a^{ - 2}} \times {a^0}$ will be

$= \left( {{a^{6 - 4}}} \right) \times {a^{ - 2}} \times {a^0} $

$= {a^2} \times {a^{ - 2}} \times 1 $

$= {a^{2 + ( - 2)}} $

$= 1 $ 

15. Find $\mathbf{{27^p} \div {27^2}}$.

Ans: Given: ${27^p} \div {27^2}$

We need to find the given expression.

$\frac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}}$ Therefore, ${27^p} \div {27^2}$ will be

$= {\left( {{3^3}} \right)^p} \div {\left( {{3^3}} \right)^2} $

$= \dfrac{{{3^{3p}}}}{{{3^6}}} $

$= {3^{3p - 6}} $

$= {3^{3(p - 2)}} $ 

16. Express each of the following as product of prime factor

$\mathbf{702}$

Ans: We need to express the given expression as product of prime factor

Therefore, $702$ can be written as a product of prime factors as

$702 = 2 \times 3 \times 3 \times 3 \times 13 $

$= {2^1} \times {3^3} \times {13^1} $

$\mathbf{33275}$

Ans: Given: $33275$

We need to express the given expression as a product of prime factors.

Therefore, $33275$ can be written as a product of prime factors as

$33275 = 5 \times 5 \times 11 \times 11 \times 11 $

$= {5^2} \times {11^3} $

17. Using the laws find

$\mathbf{\left( {{{\left( {{3^3}} \right)}^2} \times {3^2}} \right) \div {3^7}}$

Ans: Given:  $\left( {{{\left( {{3^3}} \right)}^2} \times {3^2}} \right) \div {3^7}$

${a^m} \times {a^n} = {a^{m + n}} $ 

Therefore, the value of $\left( {{{\left( {{3^3}} \right)}^2} \times {3^2}} \right) \div {3^7}$ will be

$= \left( {{3^6} \times {3^2}} \right) \div {3^7} $

$= \left( {{3^{6 + 2}}} \right) \div {3^7} $

$= {3^8} \div {3^7} $

$= {3^{8 - 7}} $

$= 3 $ 

$\mathbf{\dfrac{{{3^6}{a^8}{b^4}}}{{{3^2}{a^2}{b^3}}}}$

Ans: Given:  $\dfrac{{{3^6}{a^8}{b^4}}}{{{3^2}{a^2}{b^3}}}$

${a^m} \times {a^n} = {a^{m + n}} $ Therefore, the value of $\dfrac{{{3^6}{a^8}{b^4}}}{{{3^2}{a^2}{b^3}}}$ will be

$= \dfrac{{{3^6}{a^8}{b^4}}}{{{3^2}{a^2}{b^3}}} $

$= {3^{6 - 2}} \times {a^{8 - 2}} \times {b^{4 - 3}} $

$= {3^4} \times {a^6} \times {b^1} $

$= 81{a^6}{b^1} $ 

18. Express each of the following as product of prime factors

$\mathbf{729 \times 625}$

Therefore, $729 \times 625$ can be written as a product of prime factors as

$729 = 3 \times 3 \times 3 \times 3 \times 3 \times 3 $ 

$= {3^6} $ 

$625 = 5 \times 5 \times 5 \times 5 $

$\therefore 729 \times 625 = {3^6} \times {5^4} $

$\mathbf{1024 \times 216}$

Ans: Given: $1024 \times 216$

Therefore, $1024 \times 216$ can be written as a product of prime factors as

\[\begin{align} & 1024=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2={{2}^{10}} \\ & 216=2\times 2\times 2\times 3\times 3\times 3={{2}^{3}}\times {{3}^{3}} \\  & \therefore 1024\times 216={{2}^{10}}\times \ {{2}^{3}}\times {{3}^{3}} \\  & \,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ={{2}^{10+3}}\times {{3}^{3}} \\  & \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ={{2}^{13}}\times {{3}^{3}} \\ \end{align}\]

19. Express the following as standard form

$\mathbf{3,68,878}$

Ans: Given: $3,68,878$

We need to express the given number as a standard form.

We will write the given numbers as a multiple of power of $10.$

Therefore, the standard form of $3,68,878$ will be

$= 3.68878 \times 100000 $

$= 3.68878 \times {10^5} $ 

$\mathbf{4,78,25,00,000}$

Ans: Given: $4,78,25,00,000$

Therefore, the standard form of $4,78,25,00,000$ will be

$= 4.7825 \times 1000000000 $

$= 4.7825 \times {10^9} $ 

$\mathbf{5706.983}$

Ans: Given: $5706.983$

Therefore, the standard form of $5706.983$ will be

$= 5.706983 \times 1000 $

$= 5.706983 \times {10^3} $ 

20. Find the numbers

$\mathbf{8 \times {10^5} + 2 \times {10^2} + 4 \times {10^1}}$

Ans: Given: $8 \times {10^5} + 2 \times {10^2} + 4 \times {10^1}$

We need to solve the given expression.

We will solve the exponents and then add them.

Therefore, $8 \times {10^5} + 2 \times {10^2} + 4 \times {10^1}$ will be 

$= 8 \times 100000 + 0 \times 0 + 2 \times 100 + 4 \times 10 $

$= 800000 + 0 + 0 + 200 + 40 $

$= 8,00,240 $ 

$\mathbf{4 \times {10^4} + 6 \times {10^3} + 2 \times {10^2} + 1 \times {10^0}}$

Ans: Given: $4 \times {10^4} + 6 \times {10^3} + 2 \times {10^2} + 1 \times {10^0}$

Therefore, $4 \times {10^4} + 6 \times {10^3} + 2 \times {10^2} + 1 \times {10^0}$ will be 

$= 4 \times 10000 + 6 \times 1000 + 2 \times 100 + 1 \times 1 $

$= 40000 + 6000 + 200 + 1 $

$= 46,201 $ 

$\mathbf{5 \times {10^4} + 7 \times {10^2} + 5 \times {10^0}}$

Ans: Given: $5 \times {10^4} + 7 \times {10^2} + 5 \times {10^0}$

Therefore, $5 \times {10^4} + 7 \times {10^2} + 5 \times {10^0}$ will be 

$= 5 \times 10000 + 7 \times 100 + 5 \times 1 $

$= 50000 + 700 + 5 $

$= 50,705 $ 

Definition of Exponent

The exponent tells us how many times a number should be multiplied by itself to get the desired result. Thus any number (suppose a) raised to power ‘n’ can be expressed as:

a\[^{n}\] = a x a x a x a x a x a…. x a(n times)

Here a can be any number and n is the natural number.

a\[^{n}\] is also called the n\[^{th}\] power of a.

In this ‘a’ is the base and ‘n’ is the exponent or index or power.

 ‘a’ is multiplied ‘n’ times, It is a method of repeated multiplication.

a\[^{m}\] . a\[^{n}\] = a\[^{(m+n)}\]

(a\[^{m}\])\[^{n}\] = a\[^{mn}\]

(ab)\[^{n}\] = a\[^{n}\]b\[^{n}\]

(\[\frac{a}{b}\])\[^{n}\] = \[\frac{a^{n}}{b^{n}}\]

\[\frac{a^{m}}{a^{n}}\] = a\[^{m-n}\]

\[\frac{a^{m}}{a^{n}}\] = \[\frac{1}{a^{n-m}}\]

a\[^{0}\] = 1

Multiplying Powers With the Same Base

When the bases are the same then we add the exponents. 

a\[^{m}\] x a\[^{n}\] = a\[^{(m+n)}\]

In a similar way, if ‘a’ is a non-zero integer or a non-zero rational number and m and n are positive integers, then

Similarly (\[\frac{a}{b}\])\[^{m}\] x (\[\frac{a}{b}\])\[^{n}\] = (\[\frac{a}{b}\])\[^{m+n}\]   

 Exponents can be added only when the bases are the same. 

 Exponents cannot be added if the bases are not the same.

Dividing Powers with the Same Base

In division, if the bases are the same then we need to subtract the exponents.

a\[^{m}\]  ÷  a\[^{n}\] =  \[\frac{a^{m}}{a^{n}}\] = a\[^{m-n}\]   

Where m and n are whole number and m<n;

We can generalize that if a is a non-zero integer or q non-zero rational number and m and n are positive integers, such that m<n;

a\[^{m}\]  ÷  a\[^{n}\] = a\[^{m-n}\] if m<n, then a\[^{m}\]  ÷  a\[^{n}\] = \[\frac{1}{a^{(n-m)}}\]    

Similarly, (\[\frac{a}{b}\])\[^{m}\] ÷ (\[\frac{a}{b}\])\[^{n}\] = (\[\frac{a}{b}\])\[^{m-n}\]  

Power of a Power

In the power of a power you need multiply the powers

In general, for any non-integer a (a\[^{m}\])\[^{n}\] = a\[^{m \times n}\] = a\[^{mn}\]

Multiplying Power with the Same Exponent

In general, for any non-zero integer a,b

a\[^{m}\] x b\[^{m}\] = (a x b)\[^{m}\] = (ab)\[^{m}\]

Negative Exponents

If the exponent is negative we need to change it into a positive exponent by writing the same in the denominator and 1 in the numerator.

If ‘a’ is a non-zero integer or a non-zero rational number and m is a positive integer, then a\[^{-m}\] is the reciprocal of, i.e., 

a\[^{-m}\] = \[\frac{1}{a^{m}}\], if we take a as p/q then 

(\[\frac{p}{q}\])\[^{-m}\] = \[\frac{1}{(\frac{p}{q})^{m}}\] = (\[\frac{q}{p}\])\[^{m}\]

Also, \[\frac{1}{a^{-m}}\] = a\[^{m}\]  

Similarly, (\[\frac{a}{b}\])\[^{-m}\] = (\[\frac{b}{a}\])\[^{m}\], where n is a positive integer

Power with Exponent Zero

If the exponent is 0 then you get the result 1 whatever the base is.

If ‘a’ is a non-zero integer or a non-zero rational number then, 

Similarly, (\[\frac{a}{b}\])\[^{0}\] = 1

Fractional Exponent

In fractional exponent, we observe that the exponent is in fraction form.

a\[^{\frac{1}{n}}\], where a is called the base and 1/n is called an exponent or power. It is denoted as \[\sqrt[n]{a}\] is called as the nth root of a.

Some Rules to Remember While Calculating the Power of a Number

Rule 1: Any number to the zero power is equal to 1.

Rule 2: Any number to the first power is equal to the number itself.

Rule 3: If the base to which we are calculating power is negative, then odd power results in negative values and even power results in positive values.

For example:

(-4)\[^{3}\]= -64

4\[^{2}\] = 16

Rule 4: The exponent comes before the multiplication in the order of operations. We can add in the parentheses if it helps us to solve the question.

(2 x 3)\[^{2}\] = 6\[^{2}\] = 36  

2 x 3\[^{2}\] = 2 x 9 = 18

The sequence formed by powers of a number (exponent starting from 0 and having integral values) is a geometric progression with a first-term equal to 1 and common ratio being equal to the base.

Look at the pattern below:

2\[^{0}\] = 1

2\[^{1}\] = 2

2\[^{2}\] = 2 x 2 = 4

2\[^{3}\] = 2 x 2 x 2 = 8

2\[^{4}\] = 2 x 2 x 2 x 2 = 16

2\[^{5}\] = 2 x 2 x 2 x 2 x 2 = 32

A common mistake is to multiply the base and exponent together, which is not the correct way to calculate the power of a number.

For example: 

4\[^{3}\] = 4 x 3 = 12 (Wrong)

4\[^{3}\] = 4 x 4 x 4 = 64 (Right)

Why are the Important Questions from Vedantu Useful for Class 7 Maths Chapter 13 - Exponents and Powers?

Embark on a learning journey with Vedantu's Essential Questions for Class 7 Maths Chapter 13 - Exponents and Powers. These unique questions serve as friendly guides, empowering you to approach mathematics with confidence!

1. Focused Topics: Tackle important concepts like "Power Patterns" and "Squaring Shortcuts" efficiently, making studying a breeze.

2. Exam Readiness: Feel confident and reduce exam worries by practicing questions aligned with what you'll face in your upcoming test.

3. Concept Reinforcement: Solidify your understanding of fundamental ideas like "Powers of 10" through targeted questions that reinforce what you've learned.

4. Time Mastery: Learn to manage your time wisely by practicing with questions that mirror the ones you'll find in your exam.

5. Self-Assessment: Track your progress and discover your strengths with questions designed for self-evaluation, helping you become a maths master.

6. Strategic Scoring: Follow a smart approach for higher scores by focusing on crucial topics such as "Negative Ninja Rule" and "Cubing Clue."

7. Comprehensive Coverage: Explore a wide array of topics, from "Zero Power Zen" to "Product Power," ensuring you understand every aspect of Exponents and Powers.

8. Confidence Booster: Gain confidence for your exam, as these questions are like a secret weapon, preparing you for success in your maths journey.

Exponents play a crucial role in algebra, simplifying repeated multiplication. The exponent indicates how many times a number multiplies itself. It's important to note that any number to the power of 0 equals 1. When expressing with exponents, attention to negative signs and parentheses is vital. Exponents come in four types: positive, negative, zero, and rational/fraction. To delve deeper into this chapter, access the Class 7 Maths Chapter 13 extra questions PDF on Vedantu’s website or app. This resource enhances understanding and consolidates knowledge about exponents in a user-friendly format.

FAQs on Important Questions for CBSE Class 7 Maths Chapter 13 - Exponents and Powers

1. How do powers and exponents differ from one another?

An exponent is the number of times a number is involved in a multiplication, whereas power refers to the number of times a number is multiplied by itself, indicating the number you receive elevating a number to. Powers and indices are other names for exponents. Exponent refers to a quantity that reflects the power to which the number is raised, whereas power is an expression that expresses repeated multiplication of the same number. In mathematical operations, both names are frequently used interchangeably.

2. What are exponents?

The number being multiplied is defined as the base number when it is multiplied by itself an indefinite number of times, and the number of times it is being multiplied is known as the exponent .

3. What are powers?

To specify specifically how many times a number should be multiplied, mathematicians use the term " power ." It is a statement that, in simple English, denotes the repeated multiplication of the same integer. Raising a number to a power is a way to convey the phrase.

4. What is the exponentiation of 10,00,000?

In exponents, we can express 10,00,000 in the following ways: 10,00,000 = 10 * 10 *10 * 10 *10*10 = 10^6

5. How are these exponents easily solved?

You must repeatedly multiply the base number by the amount of factors that make up a basic exponent in order to solve it. The numbers must have the same base and exponent in order to add or remove exponents.

Chapterwise Important Questions for CBSE Class 7 Maths

Cbse study materials.

• NCERT Solutions
• NCERT Class 7
• NCERT 7 Maths
• Chapter 13 Exponents And Powers

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers

* According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 11.

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers are given here in detail. Maths is a subject which requires understanding and reasoning skills accompanied by logic. Along with this, students should practise solving Maths problems regularly. Students of Class 7 are suggested to solve NCERT Solutions  Chapter 13 to strengthen their fundamentals and be able to solve questions that are usually asked in the examination.

A total of 3 exercises are present in Chapter 13 – Exponents and Powers of NCERT Solutions for Class 7 Maths . These exercises cover various concepts mentioned in the chapter, which are given below.

• Laws of Exponents
• Multiplying Powers with the Same Base
• Dividing Powers with the Same Base
• Taking Power of a Power
• Dividing Powers with the Same Exponents
• Miscellaneous Examples Using the Laws of Exponents
• Decimal Number System
• Expressing Large Numbers in the Standard Form

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Exercise 13.1 Solutions

Exercise 13.2 Solutions

Exercise 13.3 Solutions

Access Answers to Maths NCERT Solutions for Class 7 Chapter 13 – Exponents and Powers

Exercise 13.1 Page: 252

1. Find the value of:

The above value can be written as,

= 2 × 2 × 2 × 2 × 2 × 2

= 9 × 9 × 9

= 5 × 5 × 5 × 5

2. Express the following in exponential form:

(i) 6 × 6 × 6 × 6

The given question can be expressed in the exponential form as 6 4 .

The given question can be expressed in the exponential form as t 2 .

(iii) b × b × b × b

The given question can be expressed in the exponential form as b 4 .

(iv) 5 × 5× 7 × 7 × 7

The given question can be expressed in the exponential form as 5 2 × 7 3 .

(v) 2 × 2 × a × a

The given question can be expressed in the exponential form as 2 2 × a 2 .

(vi) a × a × a × c × c × c × c × d

The given question can be expressed in the exponential form as a 3 × c 4 × d.

3. Express each of the following numbers using the exponential notation:

The factors of 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2

So it can be expressed in the exponential form as 2 9 .

The factors of 343 = 7 × 7 × 7

So it can be expressed in the exponential form as 7 3 .

The factors of 729 = 3 × 3 × 3 × 3 × 3 × 3

So it can be expressed in the exponential form as 3 6 .

The factors of 3125 = 5 × 5 × 5 × 5 × 5

So it can be expressed in the exponential form as 5 5 .

4. Identify the greater number, wherever possible, in each of the following.

(i) 4 3 or 3 4

The expansion of 4 3 = 4 × 4 × 4 = 64

The expansion of 3 4 = 3 × 3 × 3 × 3 = 81

So, 4 3 < 3 4

Hence, 3 4 is the greater number.

(ii) 5 3 or 3 5

The expansion of 5 3 = 5 × 5 × 5 = 125

The expansion of 3 5 = 3 × 3 × 3 × 3 × 3= 243

125 < 243

So, 5 3 < 3 5

Hence, 3 5 is the greater number.

(iii) 2 8 or 8 2

The expansion of 2 8 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256

The expansion of 8 2 = 8 × 8= 64

256 > 64

So, 2 8 > 8 2

Hence, 2 8 is the greater number.

(iv) 100 2 or 2 100

The expansion of 100 2 = 100 × 100 = 10000

The expansion of 2 100

2 10 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024

2 100 = 1024 × 1024 ×1024 × 1024 ×1024 × 1024 × 1024 × 1024 × 1024 × 1024 = (1024) 10

100 2 < 2 100

Hence, 2 100 is the greater number.

(v) 2 10 or 10 2

The expansion of 2 10 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024

The expansion of 10 2 = 10 × 10= 100

1024 > 100

So, 2 10 > 10 2

Hence, 2 10 is the greater number.

5. Express each of the following as a product of powers of their prime factors:

Factors of 648 = 2 × 2 × 2 × 3 × 3 × 3 × 3

= 2 3 × 3 4

Factors of 405 = 3 × 3 × 3 × 3 × 5

Factors of 540 = 2 × 2 × 3 × 3 × 3 × 5

= 2 2 × 3 3 × 5

Factors of 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5

= 2 4 × 3 2 × 5 2

6. Simplify:

(i) 2 × 10 3

The above question can be written as,

= 2 × 10 × 10 × 10

(ii) 7 2 × 2 2

= 7 × 7 × 2 × 2

(iii) 2 3 × 5

= 2 × 2 × 2 × 5

(iv) 3 × 4 4

= 3 × 4 × 4 × 4 × 4

(v) 0 × 10 2

= 0 × 10 × 10

(vi) 5 2 × 3 3

= 5 × 5 × 3 × 3 × 3

(vii) 2 4 × 3 2

= 2 × 2 × 2 × 2 × 3 × 3

(viii) 3 2 × 10 4

= 3 × 3 × 10 × 10 × 10 × 10

= 9 × 10000

7. Simplify:

(i) (– 4) 3

The expansion of -4 3

= – 4 × – 4 × – 4

= – 64

(ii) (–3) × (–2) 3

The expansion of (-3) × (-2) 3

= – 3 × – 2 × – 2 × – 2

= – 3 × – 8

(iii) (–3) 2 × (–5) 2

The expansion of (-3) 2 × (-5) 2

= – 3 × – 3 × – 5 × – 5

(iv) (–2) 3 × (–10) 3

The expansion of (-2) 3 × (-10) 3

= – 2 × – 2 × – 2 × – 10 × – 10 × – 10

= – 8 × – 1000

8. Compare the following numbers:

(i) 2.7 × 10 12 ; 1.5 × 10 8

By observing the question

Comparing the exponents of base 10,

2.7 × 10 12 > 1.5 × 10 8

(ii) 4 × 10 14 ; 3 × 10 17

4 × 10 14 < 3 × 10 17

Exercise 13.2 Page: 260

1. Using laws of exponents, simplify and write the answer in exponential form:

(i) 3 2 × 3 4 × 3 8

By the rule of multiplying the powers with the same base = a m × a n = a m + n

= (3) 2 + 4 + 8

(ii) 6 15 ÷ 6 10

By the rule of dividing the powers with the same base = a m ÷ a n = a m – n

= (6) 15 – 10

(iii) a 3 × a 2

= (a) 3 + 2

(iv) 7 x × 7 2

= (7) x + 2

(v) (5 2 ) 3 ÷ 5 3

By the rule of taking the power of as power = (a m ) n = a mn

(5 2 ) 3 can be written as = (5) 2 × 3

Now, 5 6 ÷ 5 3

= (5) 6 – 3

(vi) 2 5 × 5 5

By the rule of multiplying the powers with the same exponents = a m × b m = ab m

= (2 × 5) 5

(vii) a 4 × b 4

= (a × b) 4

(viii) (3 4 ) 3

(3 4 ) 3 can be written as = (3) 4 × 3

(ix) (2 20 ÷ 2 15 ) × 2 3

(2 20 ÷ 2 15 ) can be simplified as,

= (2) 20 – 15

2 5 × 2 3 can be simplified as,

= (2) 5 + 3

(x) 8 t ÷ 8 2

= (8) t – 2

2. Simplify and express each of the following in exponential form:

(i) (2 3 × 3 4 × 4)/ (3 × 32)

Factors of 32 = 2 × 2 × 2 × 2 × 2

Factors of 4 = 2 × 2

= (2 3 × 3 4 × 2 2 )/ (3 × 2 5 )

= (2 5 × 3 4 ) / (3 × 2 5 )

= 2 0 × 3 3

(ii) ((5 2 ) 3 × 5 4 ) ÷ 5 7

= (5 6 × 5 4 ) ÷ 5 7

= 5 10 ÷ 5 7

(iii) 25 4 ÷ 5 3

(25) 4 can be written as = (5 × 5) 4

= 5 8 ÷ 5 3

(iv) (3 × 7 2 × 11 8 )/ (21 × 11 3 )

Factors of 21 = 7 × 3

= (3 × 7 2 × 11 8 )/ (7 × 3 × 11 3 )

= 3 1-1 × 7 2-1 × 11 8 – 3

= 3 0 × 7 × 11 5

= 1 × 7 × 11 5

(v) 3 7 / (3 4 × 3 3 )

= 3 7 / 3 7

(vi) 2 0 + 3 0 + 4 0

= 1 + 1 + 1

(vii) 2 0 × 3 0 × 4 0

= 1 × 1 × 1

(viii) (3 0 + 2 0 ) × 5 0

= (1 + 1) × 1

(ix) (2 8 × a 5 )/ (4 3 × a 3 )

(4) 3 can be written as = (2 × 2) 3

= (2 8 × a 5 )/ (2 6 × a 3 )

(x) (a 5 /a 3 ) × a 8

= a 2 × a 8

(xi) (4 5 × a 8 b 3 )/ (4 5 × a 5 b 2 )

= 4 0 × (a 3 b)

= 1 × a 3 b

(xii) (2 3 × 2) 2

3. Say true or false and justify your answer:

(i) 10 × 10 11 = 100 11

Let us consider Left Hand Side (LHS) = 10 × 10 11

Now, consider Right Hand Side (RHS) = 100 11

= (10 × 10) 11

= (10 1 + 1 ) 11

= (10 2 ) 11

By comparing LHS and RHS,

Hence, the given statement is false.

(ii) 2 3 > 5 2

Let us consider LHS = 2 3

Expansion of 2 3 = 2 × 2 × 2

Now, consider RHS = 5 2

Expansion of 5 2 = 5 × 5

LHS < RHS

2 3 < 5 2

(iii) 2 3 × 3 2 = 6 5

Let us consider LHS = 2 3 × 3 2

Expansion of 2 3 × 3 2 = 2 × 2 × 2 × 3 × 3

Now, consider RHS = 6 5

Expansion of 6 5 = 6 × 6 × 6 × 6 × 6

(iv) 3 0 = (1000) 0

Let us consider LHS = 3 0

Now, consider RHS = 1000 0

3 0 = 1000 0

Hence, the given statement is true.

4. Express each of the following as a product of prime factors only in exponential form:

(i) 108 × 192

The factors of 108 = 2 × 2 × 3 × 3 × 3

= 2 2 × 3 3

The factors of 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3

= (2 2 × 3 3 ) × (2 6 × 3)

= 2 8 × 3 4

The factors of 270 = 2 × 3 × 3 × 3 × 5

= 2 × 3 3 × 5

(iii) 729 × 64

The factors of 64 = 2 × 2 × 2 × 2 × 2 × 2

= (3 6 × 2 6 )

= 3 6 × 2 6

The factors of 768 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3

5. Simplify:

(i) ((2 5 ) 2 × 7 3 )/ (8 3 × 7)

8 3 can be written as = (2 × 2 × 2) 3

= ((2 5 ) 2 × 7 3 )/ ((2 3 ) 3 × 7)

= (2 10 × 7 3 )/ (2 9 × 7)

= 2 × 7 × 7

(ii) (25 × 5 2 × t 8 )/ (10 3 × t 4 )

25 can be written as = 5 × 5

10 3 can be written as = 10 3

= (5 × 2) 3

= 5 3 × 2 3

= (5 2 × 5 2 × t 8 )/ (5 3 × 2 3 × t 4 )

= (5 4 × t 8 )/ (5 3 × 2 3 × t 4 )

= (5 × t 4 )/ (2 × 2 × 2)

= (5t 4 )/ 8

(iii) (3 5 × 10 5 × 25)/ (5 7 × 6 5 )

10 5 can be written as = (5 × 2) 5

= 5 5 × 2 5

6 5 can be written as = (2 × 3) 5

= 2 5 × 3 5

Then we have,

= (3 5 × 5 5 × 2 5 × 5 2 )/ (5 7 × 2 5 × 3 5 )

= (3 5 × 5 7 × 2 5 )/ (5 7 × 2 5 × 3 5 )

= (3 5 – 5 × 5 7 – 7 × 2 5 – 5 )

Exercise 13.3 Page: 263

1. Write the following numbers in the expanded forms:

The expanded form of the number 279404 is,

= (2 × 100000) + (7 × 10000) + (9 × 1000) + (4 × 100) + (0 × 10) + (4 × 1)

Now we can express it using powers of 10 in the exponent form,

= (2 × 10 5 ) + (7 × 10 4 ) + (9 × 10 3 ) + (4 × 10 2 ) + (0 × 10 1 ) + (4 × 10 0 )

(b) 3006194

The expanded form of the number 3006194 is,

= (3 × 1000000) + (0 × 100000) + (0 × 10000) + (6 × 1000) + (1 × 100) + (9 × 10) + (4 × 1)

= (3 × 10 6 ) + (0 × 10 5 ) + (0 × 10 4 ) + (6 × 10 3 ) + (1 × 10 2 ) + (9 × 10 1 ) + (4 × 10 0 )

(c) 2806196

The expanded form of the number 2806196 is,

= (2 × 1000000) + (8 × 100000) + (0 × 10000) + (6 × 1000) + (1 × 100) + (9 × 10) + (6 × 1)

= (2 × 10 6 ) + (8 × 10 5 ) + (0 × 10 4 ) + (6 × 10 3 ) + (1 × 10 2 ) + (9 × 10 1 ) + (6 × 10 0 )

The expanded form of the number 120719 is,

= (1 × 100000) + (2 × 10000) + (0 × 1000) + (7 × 100) + (1 × 10) + (9 × 1)

= (1 × 10 5 ) + (2 × 10 4 ) + (0 × 10 3 ) + (7 × 10 2 ) + (1 × 10 1 ) + (9 × 10 0 )

The expanded form of the number 20068 is,

= (2 × 10000) + (0 × 1000) + (0 × 100) + (6 × 10) + (8 × 1)

= (2 × 10 4 ) + (0 × 10 3 ) + (0 × 10 2 ) + (6 × 10 1 ) + (8 × 10 0 )

2. Find the number from each of the following expanded forms:

(a) (8 × 10) 4 + (6 × 10) 3 + (0 × 10) 2 + (4 × 10) 1 + (5 × 10) 0

The expanded form is,

= (8 × 10000) + (6 × 1000) + (0 × 100) + (4 × 10) + (5 × 1)

= 80000 + 6000 + 0 + 40 + 5

(b) (4 × 10) 5 + (5 × 10) 3 + (3 × 10) 2 + (2 × 10) 0

= (4 × 100000) + (0 × 10000) + (5 × 1000) + (3 × 100) + (0 × 10) + (2 × 1)

= 400000 + 0 + 5000 + 300 + 0 + 2

(c) (3 × 10) 4 + (7 × 10) 2 + (5 × 10) 0

= (3 × 10000) + (0 × 1000) + (7 × 100) + (0 × 10) + (5 × 1)

= 30000 + 0 + 700 + 0 + 5

(d) (9 × 10) 5 + (2 × 10) 2 + (3 × 10) 1

= (9 × 100000) + (0 × 10000) + (0 × 1000) + (2 × 100) + (3 × 10) + (0 × 1)

= 900000 + 0 + 0 + 200 + 30 + 0

3. Express the following numbers in standard form:

(i) 5,00,00,000

The standard form of the given number is 5 × 10 7

(ii) 70,00,000

The standard form of the given number is 7 × 10 6

(iii) 3,18,65,00,000

The standard form of the given number is 3.1865 × 10 9

(iv) 3,90,878

The standard form of the given number is 3.90878 × 10 5

(v) 39087.8

The standard form of the given number is 3.90878 × 10 4

(vi) 3908.78

The standard form of the given number is 3.90878 × 10 3

4. Express the number appearing in the following statements in standard form.

(a) The distance between Earth and Moon is 384,000,000 m.

The standard form of the number appearing in the given statement is 3.84 × 10 8 m.

(b) Speed of light in a vacuum is 300,000,000 m/s.

The standard form of the number appearing in the given statement is 3 × 10 8 m/s.

(c) Diameter of the Earth is 1,27,56,000 m.

The standard form of the number appearing in the given statement is 1.2756 × 10 7 m.

(d) Diameter of the Sun is 1,400,000,000 m.

The standard form of the number appearing in the given statement is 1.4 × 10 9 m.

(e) In a galaxy, there are, on average, 100,000,000,000 stars.

The standard form of the number appearing in the given statement is 1 × 10 11 stars.

(f) The universe is estimated to be about 12,000,000,000 years old.

The standard form of the number appearing in the given statement is 1.2 × 10 10 years old.

(g) The distance of the Sun from the centre of the Milky Way Galaxy is estimated to be 300,000,000,000,000,000,000 m.

The standard form of the number appearing in the given statement is 3 × 10 20 m.

(h) 60,230,000,000,000,000,000,000 molecules are contained in a drop of water weighing 1.8 gm.

The standard form of the number appearing in the given statement is 6.023 × 10 22 molecules.

(i) The Earth has 1,353,000,000 cubic km of seawater.

The standard form of the number appearing in the given statement is 1.353 × 10 9 cubic km.

(j) The population of India was about 1,027,000,000 in March 2001.

The standard form of the number appearing in the given statement is 1.027 × 10 9 .

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NCERT Solutions Class 7 Maths Chapter 13 Exponents and Powers

Exponents are a way to write very big numbers in a concise and readable manner. The NCERT Solutions for Class 7 maths Chapter 13 Exponents and Powers comprises the rules and laws framed around the exponents. Large numbers are often encountered in mathematics , science, and geography. It becomes not only difficult to read them, but also it is tricky to do calculations with them. Exponents and powers are there to simplify this process by making the numbers easier to read and operate. Thus, these NCERT solutions Class 7 maths Chapter 13 will teach the students how to write the long number in short form notation.

Hence, 100,000 can be written as 10 5 which means 10 x 10 x 10 x 10 x 10. So here, 10 is called the base, and 5 is called the exponent , and the mathematical way to read it is 10 raised to the power of five, or it can be said that 10 5 is the exponential form of the number 100,000. These powers have been given specific names in mathematics, such as the power 2 is read as squared, so 10 2 is 10 ‘square’ while 10 3 or 10 raised to the power of three is read as 10 ‘cube’. The NCERT Class 7 maths solutions Chapter 13 Exponents and Powers are given below and also find some of these in the exercises given below.

• NCERT Solutions Class 7 Maths Chapter 13 Ex 13.1
• NCERT Solutions Class 7 Maths Chapter 13 Ex 13.2
• NCERT Solutions Class 7 Maths Chapter 13 Ex 13.3

NCERT Solutions for Class 7 Maths Chapter 13 PDF

When a quantity is multiplied by itself a bunch of times, the exponent indicates how many times it has been multiplied. They're also known as 'power.' In mathematics, there are special rules for resolving problems using exponents, which can be learned from the NCERT solutions Class 7 maths Chapter 13 given below:

☛ Download Class 7 Maths NCERT Solutions Chapter 13

NCERT Class 7 Maths Chapter 13   Download PDF

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers

Exponents are commonly used in algebraic expressions and can be multiplied in the same way that other numbers are multiplied. Exponents, which indicate repetitive multiplication, can easily be simplified using a few simple properties. The basic structure of an exponent's writing is x y , where x represents the base and y represents the exponent. The students must make sure to learn all these facts, which are explained in detail in the NCERT Solutions Class 7 Maths Chapter 13 Exponents and Powers given below.

• Class 7 Maths Chapter 13 Ex 13.1 - 8 Questions
• Class 7 Maths Chapter 13 Ex 13.2 - 5 Questions
• Class 7 Maths Chapter 13 Ex 13.3 - 4 Questions

☛ Download Class 7 Maths Chapter 13 NCERT Book

Topics Covered: The Class 7 maths NCERT solutions Chapter 13 takes a closer look at the laws related to exponents, how to do multiplication when the base is the same, how to manage taking out power of a power and how multiplication and division of powers with same exponents are done. Also, how to deal with numbers that have exponent as zero and how large numbers can be represented in the standard form is discussed herewith.

Total Questions: The class 7 maths chapter 13 Exponents and Powers consists of 17 questions of which 12 are easy, 3 are moderately difficult and 2 are long answer type questions.

List of Formulas in NCERT Solutions Class 7 Maths Chapter 13

The NCERT solutions Class 7 maths Chapter 13 covers a lot of important concepts crucial for understanding the exponents. The main thing being how to deal when multiplication and division are encountered in the case of exponents. Thus, there are certain guidelines that need to be followed, like when numbers in the exponential form are multiplied their powers get added. Some of such important formulas covered in NCERT Solutions for Class 7 maths Chapter 13 are given below :

• Multiplication of Exponents : a x x a b = a x+b
• Division of Exponents : a x / a b = a x-b

Important Questions for Class 7 Maths NCERT Solutions Chapter 13

Ncert solutions for class 7 maths video chapter 13, faqs on ncert solutions class 7 maths chapter 13, why are ncert solutions class 7 maths chapter 13 important.

The students will get to practice a variety of questions on exponents and powers in the NCERT Solutions Class 7 Maths Chapter 13, which will ensure that they cover different kinds of numbers. With the help of examples and exercise questions, the students will gain enough confidence to deal with any problem in the exams. Also, the NCERT team has thoughtfully curated the study material after much research, which is very helpful in learning the important concepts.

What are the Important Formulas in NCERT Solutions Class 7 Maths Chapter 13?

The NCERT Solutions Class 7 Maths Chapter 13 deals with the law of exponents explaining some important rules. Some of which are: The multiplication of exponents results in the addition of their powers while the division of exponents results in the subtraction of their powers. Also, the power of power results in the multiplication of them. These are important pointers which the students will need while solving questions.

Do I Need to Practice all Questions Provided in Class 7 Maths NCERT Solutions Exponents and Powers?

Each example and question in the NCERT Solutions Class 7 Maths Exponents and Powers will help the students in memorizing the concepts which they have read in the chapter. Hence, it is beneficial for the students to solve all of them in order to increase their understanding of the exponents and powers.

How CBSE Students can utilize NCERT Solutions Class 7 Maths Chapter 13 effectively?

The students must make sure to move slowly throughout the chapter, only when they are clear of the concepts in one section then they should move ahead. An improper understanding of the previous concepts will result in confusion when approaching new concepts. Also to strengthen their learned knowledge they must ensure to practice all the solved examples too. In this way, they can utilize the NCERT Solutions Class 7 Maths Chapter 13 effectively.

Why Should I Practice NCERT Solutions Class 7 Maths Exponents and Powers Chapter 13?

The NCERT Solutions Class 7 Maths Exponents and Powers Chapter 13 has been specially designed by the expert scholars at NCERT, making it an important resource of learning. They have made sure that the concepts have been explained in simple language and all the necessary topics are covered in a comprehensive manner. The CBSE board also highly recommends studying from the NCERT books hence making it an important resource for the students to practice.

How Many Questions are there in Class 7 Maths NCERT Solutions Chapter 13 Exponents and Powers?

The Class 7 Maths Chapter 13 Exponents and Powers has 17 questions, which have various subparts as well. 12 of these are very easy as they require representation in exponential form, and 5 of them are a little towards the complex side because of the calculations involved in them.